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At line 3, the program instantiates a stack of strings, like the one in Example 5.1 on page 103. Then it goes into an infinite while loop at line 5, interactively reading a string on each iteration at line 6. If the user inputs anything other than +, -, *, /, q, or Q, the program assumes it is a number and pushes it onto the stack at line 23. If it is one of the four arithmetic operations, then the top two numbers are popped off the stack at lines 9 10 and the operation is applied to them. The result is printed at line 18 and then pushed onto the stack at line 19. The program ends when the user enters q or Q (for quit ).

Le _

Human readers tend to prefer infix to postfix notation for arithmetic expressions. The following example converts a given infix expression to postfix. EXAMPLE 5.7 Converting Infix to Postfix

Figure 1-3 Jacquard Loom Cards, photograph by Doug Jones (http://www.cs.uiowa.edu/~jones/cards/history.html).

R1R2 R1 + R2 C (c)

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24

Le _

public class TestScanner { public static void main(String[] args) { Deque<String> stack = new ArrayDeque<String>(); String line = new Scanner(System.in).nextLine(); System.out.println(line); Scanner scanner = new Scanner(line); while (scanner.hasNext()) { if (scanner.hasNextInt()) { System.out.print(scanner.nextInt() + " "); } else { String str = scanner. next(); if ("+-*/".indexOf(str) >= 0) { stack.push(str); } else if (str.equals(")")) { System.out.print(stack.pop() + " "); } } } while (!stack.isEmpty()) { System.out.print(stack.pop() + " "); } System.out.println(); } }

In his work on the analytical engine, Babbage made an important intellectual leap regarding the punched cards. In the Jacquard loom, the presence or absence of each hole in the card physically allows a colored thread to pass or stops that thread. Babbage realized that the pattern of holes could be used to represent an abstract idea such as a problem statement or the raw data required for that problem s solution. Because of the connection to the Jacquard loom, Babbage called the two main parts of his Analytic Engine the Store and the Mill , as both terms are used in the weaving industry. The Store was where numbers were held, and the Mill was where they were woven into new results. In a modern computer these same parts are called the memory unit and the central processing unit (CPU). Perhaps the key concept that separated the analytical engine from its predecessors was that it supported conditional program execution. This allows the machine to determine what to do next, based upon a condition or situation that is detected at the very moment the program is running.

An even simpler model can be obtained by nding a Thevenin equivalent for the circuit to the right of a; a in Fig. 6-2(b). Application of KVL around the outer loop gives v ib hie ie RE ib hie hfe 1 ib RE The Thevenin impedance is the driving-point impedance: v RTh hie hfe 1 RE ib 6:15

The output is:

6:16

CHAP. 1]

The Thevenin voltage is zero (computed with terminals a; a open); thus, the equivalent circuit consists only of RTh . This is shown, in a base-current frame of reference, in Fig. 6-2(c). (See Problem 6.13 for a development of the CC h-parameter model.)

( 80 30 ) * ( 40 + 50 / 10 ) 80 30 40 50 10 / + *

The tee-equivalent circuit or r-parameter model is a circuit realization based on the z parameters of 1. Applying the z-parameter de nitions of (1.10) to (1.13) to the CB small-signal equivalent circuit of Fig. 6-1(b) leads to z11 hib z12 z21 z22 hrb hob hfb hob 1 hob hrb hfb hob 6:17 6:18 6:19 6:20

The output shows that the program parsed the infix expression ( 80 30 ) * ( 40 + 50 / 10 ) to generate its postfix equivalent 80 30 40 50 10 / + *. The program uses a stack, declared at line 3, and a scanner, declared at line 6. The scanner extracts integer and string tokens from the input line. If the token is an integer, it is printed immediately, at line 9. If it is one of the four strings "+", "-", "*", or "/", it is pushed onto the stack at line 13. If it is the strings ")", then the top element of the stack is popped off and printed at line 15. After the input line has been completely parsed, the remaining elements are popped from the stack and printed at lines 19 21.

(See Problem 6.17.) Substitution of these z parameters into (1.8) and (1.9) yields hrb hfb h veb hib ie rb ic hob hob hfb 1 vcb i ic hob e hob If we now de ne rb hrb hob hrb 1 hfb hob